Wirkungsbereich

SUMME

Polynome 4. Grades 

echter B0 zum Vergleich

Grafik 1 und 
Grafik 2 anzeigen

k: 8 / 273
V0(t) = If[0 ≤ t ≤ 4, ((k * t^(2)) * (t - 4)^(2)), 0]
I = (6.94, 1.066)
H = (13.298, 0.56)
G = (11.362, 1.176)
F = (12.55, 3.816)
E = (10.394, 2.408)
D = (7, 3)
C = (14.64, 4.278)
B = (1.47, 7.28)
A = (2.716, 1.176)
f(t) = (4 - t)^(3)
g(t) = t^(3)
h(t) = ((4 - t)^(2) * (-2 + t))
p(t) = (t^(2) * (2 - t))
q(t) = (((4 - t) * (-1 + t)) * (3 - t))
r(t) = ((t * (3 - t)) * (-1 + t))
s(t) = (t * (3 - t)^(2))
w(t) = ((4 - t) * (-1 + t)^(2))
a: 1 / 6
p0(t) = If[0 ≤ t ∧ t < 1, (a * g(t)), 0]
b(x) = x < 0
c(x) = x > 4
p1(t) = If[1 ≤ t ∧ t < 2, (a * (p(t) + w(t) + r(t))), 0]
p2(t) = If[2 ≤ t ∧ t < 3, (a * (q(t) + s(t) + h(t))), 0]
p3(t) = If[3 ≤ t ∧ t < 4, (a * f(t)), 0]
B0(t) = If[0 ≤ t ∧ t < 1, p0(t), If[1 ≤ t ∧ t < 2, p1(t), If[2 ≤ t ∧ t < 3, p2(t), If[3 ≤ t ≤ 4, p3(t), 0]]]]
B1(t) = B0(t - 1)
B2(t) = B0(t - 2)
B3(t) = B0(t - 3)
summe = Sum({B0(t), B1(t), B2(t), B3(t)})
d(x) = x < 3
e(x) = x > 10
i = false
B4(t) = B0(t - 4)
B5(t) = B0(t - 5)
B6(t) = B0(t - 6)
B7(t) = B0(t - 7)
B8(t) = B0(t - 8)
B9(t) = B0(t - 9)
BS4X(t) = (x(A) * V0(t)) + (x(B) * V0(t - 1)) + (x(C) * V0(t - 2)) + (x(C) * V0(t - 3)) + (x(D) * V0(t - 4)) + (x(E) * V0(t - 5)) + (x(F) * V0(t - 6)) + (x(G) * V0(t - 7)) + (x(H) * V0(t - 8)) + (x(I) * V0(t - 9))
BS4Y(t) = (y(A) * V0(t)) + (y(B) * V0(t - 1)) + (y(C) * V0(t - 2)) + (y(C) * V0(t - 3)) + (y(D) * V0(t - 4)) + (y(E) * V0(t - 5)) + (y(F) * V0(t - 6)) + (y(G) * V0(t - 7)) + (y(H) * V0(t - 8)) + (y(I) * V0(t - 9))
BSpPoly4 = CurveCartesian(BS4X(t), BS4Y(t), t, 0, 13)
j = PolyLine(A, B, C, D, E, F, G, H, I)
J = (14.134, 4.938)
K = (14.662, 0.988)
k_{1} = Line(J, K)
BSpPoly4' = Mirror(BSpPoly4, k_{1})
L = (6.082, 3.552)
M = (5.73, 3.904)
Au = Circle(L, M)
L' = Mirror(L, k_{1})
Au' = Mirror(Au, k_{1})
V1(t) = V0(t - 1)
V2(t) = V0(t - 2)
V3(t) = V0(t - 3)
V4(t) = V0(t - 4)
V5(t) = V0(t - 5)
V6(t) = V0(t - 6)
V7(t) = V0(t - 7)
V8(t) = V0(t - 8)
V9(t) = V0(t - 9)
Summe4(t) = V0(t) + V1(t) + V2(t) + V3(t) + V4(t) + V5(t) + V6(t) + V7(t) + V8(t) + V9(t)
Text3: "V0(t)=" + V0 + ""
l = true