Flächenverhältnis

\vec F = \frac{1}{s}\left(  \begin{array}{} x+y \ y \end{array}  \right) 

Verändern Sie zuerst t.

s = 8 (slider from 1 to 20, step 1)
A = (0.2, 0.10193141289437588)
B = (0.2, 0.5019314128943759)
t = 3 (slider from 0 to 20, step 1)
At: ((x(A) * (1 + t / s)) + (t * y(A) / s), (y(A) * (1 + t / s)))
Bt: ((x(B) * (1 + t / s)) + (t * y(B) / s), (y(B) * (1 + t / s)))
C = (0.6, 0.5019314128943759)
D = (0.6, 0.10193141289437588)
Ct: ((x(C) * (1 + t / s)) + (t * y(C) / s), (y(C) * (1 + t / s)))
Dt: ((x(D) * (1 + t / s)) + (t * y(D) / s), (y(D) * (1 + t / s)))
v1, at, bt, ct, dt = Polygon(At, Bt, Ct, Dt)
v2, b, c, d, a = Polygon(B, C, D, A)
e: v1 / v2
Text2: "" + e + ""
l1 = Sequence(Sequence[Vector[(i / 5, j / 10), (i / 5 + i / 5 / s + j / 10 / s, j / 10 + j / 10 / s)], i, 1, 10], j, 1, 10)
f: (e - 1) / t
g: (f * s)
Text4: "s·∇F≈" + (LaTeX[g]) + ""
E = (2.212552188552192, 1.1844359645841134)
F = (2.3794262626262674, 1.1867536600573645)