x

f(x)=\frac{1}{x}

C(x):=\pi\int_1^x{\frac{1}{t}dt}=\pi\left(1-\frac{1}{x}\right)

y_p

Volumenberechnung

f_x(x)=\frac{1}{x^2}

f(x) = If[x > 0, 1 / x]
a = Surface(t, (cos(s) * f(t)), ((-sin(s)) * f(t)), s, 0, (2 * π), t, 1, 6)
b = CurveCartesian(t, 0, f(t), t, 0.6, 10)
A_b = (0.07190404633812153, 0.2413984162429812)
B_b = (0.8919387688783396, 0.2413957181697075)
B = Point(xAxis)
A: (1, 0)
y_p = Integral(f, 1, x(B))
fs(x) = (-f(x))
cs = Integral(fs, 1, x(B))
P: (x(B), y_p)
Intfkt = Locus(P, B)
g = Segment(P, B)
ft(t) = 1 / t^(2)
c = false
f_x(x) = 1 / x^(2)
e = Integral(f_x, 1, x(B))